more cleaning

2022/1/part 1 solution.py

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+
+with open(r'advent_of_code\2022\1\input.txt', 'r') as file:
+    input = file.read()
+
+# print(input)
+
+test_input = '''1000
+2000
+3000
+
+4000
+
+5000
+6000
+
+7000
+8000
+9000
+
+10000'''
+
+# Split the data into groups
+groups = input.split('\n\n')
+
+# Now, each element of `groups` is a string containing the numbers in one group
+# You can further split each group into individual numbers if needed
+groups = [group.split('\n') for group in groups]
+
+print(groups)
+
+# sum up each group
+sums = [sum(int(num) for num in group) for group in groups]
+
+print(sums)
+
+# show only largest sum
+print(max(sums))

2022/1/part 2 solution.py

@@ -0,0 +1,42 @@
+
+with open(r'advent_of_code\2022\1\input.txt', 'r') as file:
+    input = file.read()
+
+# print(input)
+
+test_input = '''1000
+2000
+3000
+
+4000
+
+5000
+6000
+
+7000
+8000
+9000
+
+10000'''
+
+# Split the data into groups
+groups = input.split('\n\n')
+
+# Now, each element of `groups` is a string containing the numbers in one group
+# You can further split each group into individual numbers if needed
+groups = [group.split('\n') for group in groups]
+
+# print(groups)
+
+# sum up each group
+sums = [sum(int(num) for num in group) for group in groups]
+
+# print(sums)
+
+# show top 3 largest sum
+top_3 = sorted(sums, reverse=True)[:3]
+#print(top_3)
+
+# sum of top 3 largest sum
+sum_of_top_3 = sum(top_3)
+print(sum_of_top_3)